本题目来源于试卷: 2007美国US F=MA物理竞赛，类别为 美国F=MA物理竞赛
[单选题]
An object is released frotwp 5+a kavp/ff9;a8;q ni 4dnass 0z(m rest and falls a distance nbna +mu91w 1p +r/n2jak*hyg $h$ during the first second of time. How far will it fall during the next second of time?
A. $h$
B. $2h$
C. $3h$
D. $4h$
E. $h^{2}$
参考答案: C
本题详细解析:
Using the kinematic equation for an object in free falpu8t:8rmx q -bl from rest: $d = \frac{1}{2}gt^2$.
In the first second ($t=1\,\mathrm{s}$), the distance fallen is $h = \frac{1}{2}g(1)^2 = \frac{1}{2}g$.
The *total* distance fallen in the first *two* seconds ($t=2\,\mathrm{s}$) is $d_{total} = \frac{1}{2}g(2)^2 = \frac{1}{2}g(4) = 4h$.
The distance fallen *during* the second second is the total distance at $t=2$ minus the distance at $t=1$: $d_{2nd} = d_{total} - h = 4h - h = 3h$.
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