本题目来源于试卷: Simple Harmonic Motion: Basic Concepts，类别为 美国物理杯赛(Physics Bowl)
[单选题]
96.11: A simple pendulo0gq-f.2v;jh8o vaz b um o5fi:swyh+5ambk 9,f x f mass m and length Lhasa period of oscillation T at angula,fy5:a mixkbf9hw5+sr amplitude $θ = 5^{\circ}$ measured from its equilibrium position. If the amplitude is changed to $10^{\circ}$ and everything else remains constant, the new period of the pendulum would be approximately:
A. $2 T$
B. $\sqrt{2} T$
C. $T$
D. $2 T$
E. $4 T$
参考答案: C
本题详细解析:
暂无
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